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08-31-2010, 12:24 AM #301
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09-01-2010, 12:35 PM #302
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09-01-2010, 12:48 PM #303
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09-01-2010, 02:45 PM #304
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09-03-2010, 12:23 AM #305
- Join Date: Apr 2008
- Location: Australia
- Age: 33
- Posts: 3,537
- Rep Power: 312
I'm not at school anymore but grabbed an old school book and started doing a bit of math so I can brush up on it a bit and having a bit of trouble now and again so I might be posting here a bit haha.
Anyway, I need to know how to work this out, I have worked all the other ones out, just not the ones I circled in red.
The answers to these are:
J = 0.1 and 0.0801
K = 50 and 57.7632
L = 8 and 7.5724
Help would be apprecitated if you can help me to figure out how to work this out, and I will rep if you want, thanks.
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09-05-2010, 01:47 PM #306
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09-06-2010, 04:08 PM #307
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09-12-2010, 03:26 PM #308
Solving Systems of Equations by Substitution
Question:
2x + y = 20
-5x + y = 13
I'm lost after switching the first line to 2x = 20 - y
Or, did I already mess up starting with that?
Do I not include the '2' when switching the equation?
My teacher gave us the answers, being 7 and 6. I'm not sure which one is x and which is y, but I'm sure it's just in order.
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09-12-2010, 03:48 PM #309
- Join Date: Jun 2005
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09-12-2010, 05:54 PM #310
for the first one, the numbers your teacher gave work... but not for the second
14 + 6 = 20
-35 + 6 =/= 13
I would work using the Y
2X + Y = 20 so Y = 20 - 2X
-5X + Y = 13 so Y = 13 + 5X
then
20 - 2X = 13 + 5X
20 - 13 = 5X + 2X
7 = 7X
1=X
then
2 + Y = 20
Y = 20 - 2 = 18
testing the second equation:
-5 + 18 = 13
13 = 13
so, it works...
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09-12-2010, 06:05 PM #311
Nice.
So, what I did was (This method got the answer my teachers gave me) :
2x + y = 20
6x - 5y + 12
=
y = -2x + 20
6x - 5(-2x + 20) = 12
6x + 10x - 100 = 12
16x = 112
16
[x = 7]
Then, for Y
2(7) + y = 20
14 + y = 20-14
[y = 6]
{(7,6)} Final answer.
Reps to both for the replies/help.
Good thread.Last edited by DahStoryTella; 09-12-2010 at 06:21 PM.
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09-13-2010, 06:35 AM #312
- Join Date: Jun 2005
- Location: In the squat rack, doing kickbacks.
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09-16-2010, 09:17 PM #313
hey brahs, simple physics question dunno why i cant get it
In traveling from the earth to Mars, determine at what distance (as measured from the earth) the gravitational force of the earth acting on the Spirit rover (m=174kg) is equal to the gravitational force of Mars on Spirit.
F(mars)=F(earth) amirite?
mg=G(m(earth)*m(rover))/r^2
left side being mars data and right side is earth
isolate for r.
why doesnt this work
ffuuuuuuuuuuLast edited by deltron_3030; 09-16-2010 at 10:12 PM.
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09-16-2010, 09:22 PM #314
- Join Date: Jan 2010
- Location: Tucson, Arizona, United States
- Posts: 3,054
- Rep Power: 1880
Any physics people out there? I'm terrible at physics....
Here is one problem:
A dog searching for a bone walks 3.50 m south, then 8.20 m at an angle of 30.0 degrees north of east, and finally 15.0 m west. Use graphical techniques to find the dog's resultant displacement vector.11B US Army
That feel when can't change profile name
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09-16-2010, 09:24 PM #315
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09-16-2010, 11:49 PM #316
should be pretty easy as long as you have a concept of basic trig..
you're going to end up with a drawing something like the one attatched (sorry for the crappiness, i'm no MS paint artist)
using simple trig functions, you can find the lengths of the sides of triangle (with hypotenuse 8.2). you can then use the distances youre already given to find the remaining distances. for example, the X-component of the dog's displacement vector will be 15-x (x being the length of the top of the triangle). you can use this same method to determine the Y-component (which will be y-3.5). keep in mind that the X-component will be negative.
then again, i have no idea what "use graphical techniques" is supposed to mean.
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09-19-2010, 04:26 PM #317
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09-20-2010, 05:55 PM #318
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09-20-2010, 08:25 PM #319
- Join Date: Jun 2005
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What class is that? I could be way off here I don't think I've done a problem too similar to that before but I'll give it a shot.
That is a displacement function so we'll take the derivative to get velocity. I'll show vectors with bold faced font.
v = 5.20i + (e +2ft)j
Now we can figure out the direction of travel by forming a right triangle with the x and y component vectors and finding the hypotenuse. If we want the angle with respect to the x-axis, then tan(theta) = y/x
x = 5.20
y = e +2ft
tan(theta) = (e +2ft)/5.20
We can get some values by looking at the graph. At time=0, theta=35 degrees
tan(35) = e/5.20
e= 3.64
tan(theta) = (3.64 +2ft)/5.20
at time=14s, theta= 0 degrees
tan(0) = (3.64 +2f(14))/5.20
0 = 3.64 +28f
f= -0.13
Kind of at a loss for the units though. As far as I can tell the x component of position...which should be in meters is 5.20 times t in seconds. So it would just come out in seconds. Idk..."Adversity reveals genius, prosperity conceals it."
Think about what you want in life. Then ask yourself what you're doing to achieve it.
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09-22-2010, 12:12 AM #320
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09-24-2010, 12:56 PM #321
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09-24-2010, 01:03 PM #322
- Join Date: Jun 2005
- Location: In the squat rack, doing kickbacks.
- Posts: 6,855
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09-24-2010, 01:49 PM #323
Searched it on google, but thanks for the help man, appreciate it. I have another question though, let's say i found the area of a straight line with a slope, for example the area is 2, and the time on the x-axis is 3. Would I graph it (2, 3) on the d-t graph?
Sorry If it sounds confusing, can't really explain it properly.Misc Assyrian/Chaldean
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09-25-2010, 07:17 AM #324
English letter
Hey guys
i have a task to write a formal english letter. I'm supposed to be a student who is writing to a travel agency to request a competitive bid for travel arrangements for a group trip.
This is what i made from it, If you see any mistakes or if you can form a sentence in a better and more formal way, don't hesitate to help me
Thank you !
''
Dear Mr/Mrs,
I'm writing to you about a competitive bid for travel arrangements for a group of students who are going to visit your region soon.
We are a group of 10 students and 2 teachers from Belgium. We study tourism at school and we are planning to visit Normandy in April.
We prefer staying in a hotel because we've had previous visits to foreign places and we are used to this type of accomodation. We are trying to limit the total costs to 650 euro per student.
Could you send me a bid that includes a good and payable hotel, a transport possibility, some guided tours in Normandy and an insurance.
Thank you for taking time to read this mail and I look forward to hearing from you soon.
Yours Faithfully, ''Stay Fit : )
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09-25-2010, 09:02 AM #325
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09-25-2010, 11:33 AM #326
- Join Date: Jun 2005
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Force of gravity between earth and rover= GmE/R^2 where E is the mass of the earth, and R is the distance between earth and the rover
Force of gravity between mars and rover= GmM/r^2 where M is the mass of mars, and r is the distance between mars and the rover.
GmE/R^2 = GmM/r^2
reduces to E/R^2 = M/r^2
I'll call D the distance between earth and mars. so the R is the distance between the rover and Earth. r is the distance between the rover and mars which is equal to D-R
substituting D-R for r we now have:
E/R^2 = M/((D-R)^2)
R is the distance between earth and the rover which is what you're looking for...you can either google or probably just look in the appendix in the back of your book for the mass of mars, the mass of earth, and the distance between them. Solve for R. The algebra might get a little tricky, let me know if you need any more help."Adversity reveals genius, prosperity conceals it."
Think about what you want in life. Then ask yourself what you're doing to achieve it.
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09-25-2010, 05:19 PM #327
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09-25-2010, 05:31 PM #328
- Join Date: Jun 2005
- Location: In the squat rack, doing kickbacks.
- Posts: 6,855
- Rep Power: 5785
Just gotta practice the problems till they're easy. Physics and math are subjects you can't really "study" for. You have to analyze and interpret each question differently, so it's all about practicing them to re-enforce the ideas.
If you need any help just pm me or post here I guess... i'm actually subscribed to this thread lol."Adversity reveals genius, prosperity conceals it."
Think about what you want in life. Then ask yourself what you're doing to achieve it.
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09-25-2010, 05:35 PM #329
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09-25-2010, 06:05 PM #330
Any UK law****s here?
Need to know arguments against the pleas of insanity and diminished responsibilty
I've got:
Epileptic people and diabetics are counted as insane if they have attacks IE epilepsy or hyperglycemic attacks, so it's not really fair
The law behind it dates back to 1853 M'naughten's case so it's old and outdated
The label itself.. Being labelled as insane carries a stigma through your whole life if you ever get out of the mental ward you're put it
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