there is no ball
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06-17-2014, 10:52 AM #61
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06-17-2014, 10:52 AM #62
Except that it has an upwards velocity because the balloon is going up. Therefore it'll take some time (velocity/9.81 to be exact) before the velocity of the ball reaches zero and the ball will start falling down.
No general consensus because you gave no frame of reference. Obviously there are gonna be different answers because people are using different frames of reference.
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06-17-2014, 10:53 AM #63
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06-17-2014, 10:56 AM #64
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06-17-2014, 10:57 AM #65
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06-17-2014, 10:58 AM #66
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Nah sounds like you got the joke brah
Edit: What I said is same as below post'
Extreme example, if you stuck your hand out of a rocket and let go of a tennis ball, it's not just going to lose suddenly the momentum it had and drop straight away. Similarly, if you hold a ball out and jump, if you let go as you're travelling upwards, the ball will continue to travel upwards until gravity brings it downLast edited by SirWoodbury; 06-17-2014 at 11:04 AM.
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06-17-2014, 10:58 AM #67
Gravity kicks in immediately... always.. it's not like the ball will do something then gravity turns on.
delta_x = v0 * t + 0.5 * a * t^2
up is positive, down is negative
v0 is positive, t is 0.00000 (infinite) 00000 1
a is negative 9.81 m/s ^2
So the TRUE answer is it depends on the velocity of the balloon going up.
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06-17-2014, 10:58 AM #68
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06-17-2014, 10:59 AM #69
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06-17-2014, 10:59 AM #70
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06-17-2014, 11:00 AM #71
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06-17-2014, 11:02 AM #72
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06-17-2014, 11:02 AM #73
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06-17-2014, 11:03 AM #74
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06-17-2014, 11:03 AM #75
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06-17-2014, 11:03 AM #76
ITT: UXDork schools everyone and wins the thread.
Relative to earth, the ball is traveling upward at the same velocity that the balloon is rising. Keep in mind that velocity is a vector, not a scalar. Let us say that it has a positive velocity. Once the ball is released, it must first decelerate to zero velocity (courtesy of the -9.8m/s^2 acceleration imparted by earth) before gaining a negative velocity.
Example:
We are going up at 19.6m/s. So then, is the ball. If you use the formula [ acceleration = change in velocity / change in time ], you can determine with substitution that the acceleration due to earth will take 2 seconds (at -9.8m/s^2) to bring the ball to a 0 velocity. During that time it will still be traveling (albeit more and more slowly) farther from earth. Then after that instant at the 2-second mark, it will gain a negative velocity and afterward be traveling toward earth or "down".
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06-17-2014, 11:03 AM #77
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06-17-2014, 11:04 AM #78
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06-17-2014, 11:04 AM #79MАGА 2024. I rep pаtriots, and neg anti-american phægots. "You have given out too much Reputation in the last 24 hours, try again later." most of the day, but I give when I can.
Z4 is a frauding phægot.
Jayarbie deeply defends pædophiles, like MinisterofChildGrooming.
suave2000 is a confirmed Tunneler.
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06-17-2014, 11:05 AM #80
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06-17-2014, 11:06 AM #81
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06-17-2014, 11:07 AM #82
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06-17-2014, 11:09 AM #83
- Join Date: Feb 2013
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06-17-2014, 11:10 AM #84
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06-17-2014, 11:11 AM #85
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06-17-2014, 11:11 AM #86
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06-17-2014, 11:12 AM #87
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06-17-2014, 11:13 AM #88
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06-17-2014, 11:15 AM #89
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06-17-2014, 11:19 AM #90
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