Mmmkay.
You have a quarter.
You need to create a game of chance with the quarter such that
- there are two players
- one player has a 2/3 chance of winning, and the other has a 1/3 chance of winning
if you solve the riddle, you're smarter than a
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06-16-2013, 01:14 AM #1
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06-16-2013, 01:46 AM #2
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06-16-2013, 01:58 AM #3
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06-16-2013, 02:07 AM #4
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06-16-2013, 02:15 AM #6
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06-16-2013, 02:16 AM #7
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06-16-2013, 02:19 AM #8
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06-16-2013, 02:20 AM #9
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06-16-2013, 02:28 AM #10
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06-16-2013, 02:52 AM #11
Best two out of three. There are 3 flips of the coin. One player will have to win two of the flips and the other player can only win a single flip. The only caveat will be that the player who loses two of the flips is actually the winner of the game (2/3 chance of winning) and the player who wins two of the flips is actually the loser of the game (1/3 chance of winning).
If this fits your criteria I have a riddle for you. The winner of this game is smarter than "a" what?
Edit: I'm trying to work out the problem mathematically. During the first flip of the coin you have a 50% chance of guessing heads or tails. However, this guess would only represent 1/3 of the total coin flips. So your chances of winning the first flip would be 16.5% (0.5 x 0.33). They would then have the same chance of winning the subsequent flip which they would have the same 16.5% chance of winning. The sum of the two chances would be 0.33 or 1/3. This would have to assume that only a single person is calling heads or tails during the flip for all three coin tosses.Last edited by SumDumGoi; 06-16-2013 at 03:34 AM.
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06-16-2013, 03:46 AM #12
Flip the coin 3 times. There are 8 possible outcomes.
HHH
HHT
HTH
HTT
THH
TTH
THT
TTT
If it is either of the first two--HHH or HHT--no one wins and you go back to the start.
If the outcome is HTH, HTT, THH, or TTH, player 1 wins. If the outcome is THT or TTT player 2 wins.
Player 1 wins 2/3 of the time, and player 2 1/3.Last edited by awkwrdturtle; 06-16-2013 at 04:10 AM.
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06-16-2013, 04:59 AM #13
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06-16-2013, 06:54 AM #14
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06-16-2013, 07:20 AM #15
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06-16-2013, 07:40 AM #16
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06-16-2013, 07:54 AM #17
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06-16-2013, 08:43 AM #18
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Player 1 picks a number between 1 and 3.
Player 2 picks a number between 1 and 3.
One player flips the coin, and when it lands, both reveal their number at the same time.
If they're different (2/3), the flipper wins. If they're the same(1/3), the other player wins.
Players could take turns flipping or you could have the coin flip determine who wins on a match vs no match.Last edited by pretend; 06-16-2013 at 08:48 AM.
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06-16-2013, 11:37 AM #19
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06-16-2013, 11:57 AM #20
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Player one has 3 boxes he puts the coin in one of the boxes without player two getting to see which box he puts it in. Player two has to guess which box the coin is in. If he guesses he wins if not he loses and player one wins. If nothing is allowed in the game other than the players and the single quarter then player one could turn around and put the coin in his mouth or either of his hands turn around and player two has to guess which of the 3 it is in for the same result as with the boxes.
You still didn't answer how much these *******s lift yet! >:-O
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06-16-2013, 12:02 PM #21
Each person lifts exactly 350 on the press squat bench and deadlift.
you are only allowed to create the 2/3 and 1/3 possibilities using the probability involving the flipping of a coin. You can use 400 coin flips, infinite coin flips, or only one, but you arent allowed to use other objects to create possibilities.
Hint: think of a game that could have these odds that only uses the coin and the laws of probability.
Double hint: Riemann sums
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06-16-2013, 12:32 PM #22
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06-16-2013, 01:19 PM #23
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06-16-2013, 01:30 PM #24
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06-16-2013, 01:59 PM #25
Right, but as the number of rounds of 3 flips approaches infinity, the probabilities do converge to 1/3 and 2/3.
Call the first round of 3 flips round i=0. For player 1, the probability that he wins in round i is 1/(2^(2i+1)). Sum the probability that player 1 wins across all rounds from i=0 to infinity and you get 2/3.
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06-16-2013, 02:00 PM #26
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Or does it...
http://jsfiddle.net/gGNsU/
(Chrome recommended, click Run at top)
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06-16-2013, 02:22 PM #27
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06-16-2013, 02:23 PM #28
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06-16-2013, 02:25 PM #29
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06-16-2013, 02:57 PM #30
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