anyone good at doing related rates....if so, will post question, due in 30 minutes.
edit
A runner sprints around a circular track of radius 130 m at a constant speed of 7 m/s. The runner's friend is standing at a distance 260 m from the center of the track. How fast is the distance between the friends changing when the distance between them is 260 m? (Round to 2 decimal places.)
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10-27-2009, 08:19 PM #61
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10-27-2009, 08:30 PM #62
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10-27-2009, 08:50 PM #63
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10-27-2009, 09:48 PM #64
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10-27-2009, 10:44 PM #65Code:
//Map Collision if(bass_bb_bottom > cmap_top[(y + endY[frame])/40][x/40] && map_col[(y + endY[frame])/40][x/40] == 1) { collision = true; } else if(bass_bb_top < cmap_bottom[(y - endY[frame])/40][x/40] && map_col[(y - endY[frame])/40][x/40] == 1) { collision = true; } else if(bass_bb_right > cmap_left[y/40][(x + endX[frame])/40] && map_col[y/40][(x + endX[frame])/40] == 1) { collision = true; } else if(bass_bb_left < cmap_right[y/40][(x - endX[frame])/40]&& map_col[y/40][(x - endX[frame])/40] == 1) { collision = true; }
Finally fixed it, now time to clean it up into classes
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10-28-2009, 03:41 AM #66
ok brahs I need some help on AP Calculus AB stuff. Both problems are mainly on extrema, critical numbers, derivatives, you get the idea. Here's the first one:
f(x) = X^4 - 4X^3
I know how to find f prime and double prime, but I'm not sure how to find the critical numbers of f (the original equation shown up above). Also, how do you find the inflection points? do you set whatever you got for f double prime equal to zero and solve?
Here's the second problem:
f(x) = square root of 3 times sinx + cosx
Find where f is increasing and decreasing by using f prime. Then find f double prime to determine where f is concave up and concave down.
If any of you guys can help me on this, I will love you forever (ok not like that but maybe reps involved?) Thanks!
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10-28-2009, 04:33 PM #67
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10-28-2009, 09:29 PM #68
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10-28-2009, 09:37 PM #69
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10-28-2009, 11:41 PM #70
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10-29-2009, 05:16 AM #71
- Join Date: Oct 2008
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translate this into spanish, reps for life
"SENTENCES
Argentina is the 8th largest country in the world and 2nd largest in the world.
The countries that surround/boarder Argentina is Republic of Chile, Federative Republic of Brazil, Oriental Republic of Uruguay, Atlantic Ocean, Republics of Bolivia and Paraguay.
Its total area is approximately 2.7 million km².
Argentina’s land is made up of mountains, plateaus, plains, forest.
The mountains in Argentina are some of the tallest in world, including the Cerro Aconcagua which is 6,960m tall
The Cerro Aconcagua is the tallest mountain in the Western Hemisphere.
North Part of Argentina is very hot and humid in the summers, and milder in the winters
Central Part of Argentina wet and hot summers, and cool winters.
South Argentina has warm summers and cold winters.
Pampas: This is the plains west and south from Buenos Aires
Gran Chaco: The Gran Chaco regian in the northern part of the country is seasonal dry and wet.
Mesopotamia: The land between the Parana and Uruguay rivers is called Mesopotamia.
Cuyo: West-Central Argentina is covered by Andres Mountains. To the east of that is the Cuyo region. "
iinb4googletranslatorshttp://forum.bodybuilding.com/showthread.php?t=119333531
i rep those who post in my log often
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10-29-2009, 06:16 AM #72
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10-29-2009, 07:51 PM #73
In Highschool chem I found a site, I think it was something like chemmybear.com or something like that, but it had hundreds of reaction some of them might be there, it has been 3 years since I have done a lot of this stuff so my memory is a little iffy on the site name. I usually would go there and go to the answer sheet and just type in your reaction in the search on page tool, and see if the reaction pops up, if so you have your answer.
so what I got was
magnesium nitride (3Mg+N2--->Mg3N2)
the rest I leave to you
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10-29-2009, 08:09 PM #74
could you explain that proof, because I am struggling with this e^(j*pi)+1=0
e^(j*pi)=-1===>j*pi=ln(-1)... ln(-1)=e^(j*pi/2)*pi...j*pi=e^(j*pi/2)*pi==>j=e^(j*pi/2)
so j^j would be (e^(j*pi/2))^(e^(j*pi/2)) how does this simplify to e^(-pi/2)?
do you have to use this identity? e^(j*pi*x)=cos(pi*x)+j*sin(pi*x)?
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10-29-2009, 08:20 PM #75
1.) F(x) = x^4 - 4x^3
F'=4x^3-12x^2 = 4x^2(x - 3)
Critical Values = 0,3
Set up a number line: <-----0-----3----->
Plug in numbers between each values to find when the first derivative is negative/positive.
X < 0, Negative
0<x<3, Negative
X>3, Positive
Minimum at x = 3
F"=12x^2 - 24x = 12x(x - 2)
Critical Values = 0, 2
Set up number line: <---0---2--->
Plug in numbers between each values again to find negative/positive.
x<0, Positive, Concave Up
0<x<2, Negative, Concave Down
X>2, Positive, Concave Up
2.) Is it (Squareroot 3)(sinx + cosx) or are they all under the square root?ΦKT- Misc Fraternity Crew
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10-29-2009, 08:25 PM #76
catalysts lower the activation energy. If you want to think of an exothermic reaction, you are pushing a ball up a gentle hill until you reach the top, that would be your activation energy or the energy required to start the reaction. Once the ball rolls down the hill that is the exothermic part of the reaction. The catalyst basically makes the hill "shorter" ie less energy to start the reaction rolling.
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10-30-2009, 12:37 PM #77
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11-01-2009, 12:02 PM #78
Fruit Flies phenotypes, AP Biology 2003 question 1?
This is from the AP Biology 2003
1. In fruit flies, the phenotype of eye color is determined by a certain locus. E indicates the dominant allele and e indicates the recessive allele. The cross between a male wild-type fruit fly and a female white-eye fruit fly produced the following offspring.
F1
Wild type Male =0
Wild type Female= 45
White-eyed Male= 55
White-eyed Female= 0
Brown eyed Female= 1
The wild type and white eyed individuals from the F1 generations were crossed to produce the following offspring
F2
Wild type Male =23
Wild type Female=31
White-eyed Male= 22
White-eyed Female= 24
Brown eyed Female= 0
(a) Determine the genotypes of the original parents and explain your reasoning. You may use Punnet squares to enhance your description, but the results from the Punnett squares must be discussed in your answer.
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11-01-2009, 01:52 PM #79
- Join Date: Sep 2009
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Since there are no White-eyed Female, the p1 male is dominant E.
All males being white eyed XeY means the female p1 is XeXe and this is an X-inherited gene.
No white eyed females also tell us the entire f1 female is XeXE meaning the female p1 can only be XeXe.
Basically a cross between M(XEY) and F(XeXe)
The trait is only X chromosome regulated means the fathers genotype is useless to sons and not passed on.
btw wtf u 21 doin AP bro?Misc Strength Crew
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11-02-2009, 01:55 PM #80
You are wrong.
Catalysts are substances that, when used in a reaction, provide an alternate pathway for the reaction to occur, and this alernate pathway has a lower activation energy. It may be used in the reaction but is (ideally) regenerated in the end.
A simpler way to describe it is if you know what a Maxwell Boltzmann distribution looks like (google it if not)--there is a place where the activation energy lies. Using a catalyst would cause the activation energy in that particular reaction to be shifted left, on the curve, thereby incorporating a higher fraction of particles that have a sufficient energy to react.
Also, as possibly trivial info, catalysts can be used to slow down reactions as well.Last edited by F.Liu; 11-02-2009 at 01:57 PM.
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11-02-2009, 02:56 PM #81
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11-02-2009, 07:45 PM #82
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11-02-2009, 11:47 PM #83
You wanna have the same number of each element on both sides of the equation.
So for the first one, you have 2 Hydrogens on the left but only one on the right, so adding a two in front of the HF will balance the hydrogens. But now there are 2 F's on the right and only one on the left, so you gotta balance those now too. You gotta keep playing with it until they all even out, which they will.
One thing to remember is, generally, you wanna try to balance the most complicated molecule first, then work your way down to the least complicated.
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11-03-2009, 11:15 PM #84
Need to know how to do the problem already have the answer
1. How many grams are there in 1.5x10^25 molecules of CO^2
answer: 1.1x10^3
2. What volume would the CO^2 in Problem 1 occupy at STP?
answer 5.6x10^2
3. A sample of NH^3 gas occupies 75.0 liters at STP. How many molecules is this?
answer 2.02x10^24
4.What is the mass of the sample of NH^3 in problem 3?
answer: 5.69x10^3
5. How many atoms are there in 1.3x10^22 molecules of NO^2?
answer 3.9x10^22
6. Determine the volume of a 5.0g sample of O^2?
answer: 3.5
7a. How many molecules of O^2 are in the container in problem 6?
answer 9.4x10^22
7b. How many oxygen atoms are in the container in problem 6?
answer 1.9x10^23
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11-04-2009, 04:45 AM #85
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11-04-2009, 04:02 PM #86
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11-04-2009, 07:57 PM #87
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11-05-2009, 11:13 AM #88
- Join Date: Jun 2009
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site that balances chemical equations
http://www.gregthatcher.org/Chemistr...x?StartsWith=H***** R.I.P Timothy J. Mckenny or Frvrmuscle as you know him *****
Workout log: herp derp
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11-05-2009, 04:50 PM #89
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11-05-2009, 06:38 PM #90
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