The homework help thread...(SERIOUS)

[Jeddi]

lol, yeah, I got that. By "net in-migration or net out?" Did you mean does the US have more people entering the country than exiting?

Then it'd be net in-migration.

Sorry, it just seemed worded weird to me lol

oh, thought you didnt know what i meant about us lol. I have no idea what it means, but that's what my hw is asking me

[Airror]

oh, thought you didnt know what i meant about us lol. I have no idea what it means, but that's what my hw is asking me

Yeah, I'm pretty sure it means net amount of people entering and net amount of people leaving the country.

in-migration= entering

out-migration= leaving

Makes sense actually.

[samsuperjew]

You would be surprised. I do a **** ton of admin crap. Sports med is always useful, and the basics of health and medicine are as well. Unless, of course, you plan on never have athletes get sick or injured.

i wouldn't plan to, although they probably would


i'm more looking for something that can teach me things more relevant to my training (techniques for recovery for injury/workouts, ways to organize programs etc) that will help me out now, that can also assist in a future career

[Inurthreadz]

...

Edited
In the original story, most of it is told between Mr. Mears and Kezia, and what happens between the two, because there was so much information on these two characters it was a lot easier to write about them and so most of my story was also on Mr. Mears and Kezia.
Mr. Mears is seen as not a very knowledgeable but a very religious man, as he is a preacher. When they did have to take cover from the snowstorm, it was Kezia who was teaching him how to survive and what to do so he wouldn't freeze to death. He was quick to pray about their predicament in the hut.
In my story, Mr. Mears is very similar. When they did approach the Barclay?s residence ?Mr. Mears led Kezia in prayer?. He was very nervous and awkward when they had to explain the situation, with ?a thin layer of perspiration on his palms and neck.? Kezia was also doing most of the talking and explaining with Mr. Mears just there, saying nothing.
Kezia on the otherhand, is the opposite of Mr. Mears. She is sly, sneaky and very ingenious. She was the one who was teaching Mr. Mears the survival skills, and guiding him on what to do so they would not freeze to death. ?Nor?easters usually ? a night? she explained to Mr. Mears.. What showed she was very clever, was when she ?bundled? with Mr. Mears, instead of using the ?tinderbox ? Mr. Barclays wedding gift to Mr. Hathaway? to create heat.
In my story, Kezia is also very smart, she thought for a while about what to say to explain the situation to Mr. Barclay. She even figured out there was something wrong, when ?Mr. Barclay did not act his usual way, with his boastful way of saying things.? Even though Mr. Hathaway had died, Kezia still got her way in a sense of not marrying him.
Like the original story, I made the ending seem like everything was alright and that they continued their lives as normal.

I haven't changed much. I always taught not to use commas if your going to say and after and don't finish a story with "happily ever after", didn't seem to be any wrong spellings or tenses might want to get someone else to check it just in case :P.
Maybe extend the conclusion? Didn't know if it need to be paragraphed, if not ignore that.

[Greg_Chepeian]

i is the square root of -1

therefore i to the power of i

is square root of -1 squared

= -1

i's absolute value is |1| no matter how you look at it... the overall value is still 1.. so 1 times itself is still 1.. doesnt matter whether its negative or positive... so i^i = 1.. and thats how you can prove it^^^ someone correct me if im wrong

[fortybelow]

this thread might come handy

[Arlecchino]

i wouldn't plan to, although they probably would


i'm more looking for something that can teach me things more relevant to my training (techniques for recovery for injury/workouts, ways to organize programs etc) that will help me out now, that can also assist in a future career

This is as relevant as you make it. Skill is not only using the appropriate tool at the appropriate time, but selecting the right tool for the task. The more you have to select from . . .

Most of what you are able to take at this time will not be directly relevant. Honestly, many first year programs, at least in the US, are remarkably generic. You could pick up a used ex phys text and go through it on your own, really. As well as doing other things to increase your base level of knowledge.

[TheSoldier]

Edited

thanks reps to you shyr

[Daffle]

I have a 6-8 rough draft on obesity due on Thursday!
i haven't even read

every time i read anything
someone motivate me!
every time i try and read it goes in one ea and out the other!

[TheLostSim1718]

Good job Forge and Arch

in b4 rep beg

[dean681]

Actually I think this is correct.

3Mg + N2 ---> Mg3N2
2Al + 3F2 ---> 2AlF3
2K + O2 ---> 2K2O
2Cd + I2 ---> 2CdI
3Cs + P ---> Cs3P

[TheLostSim1718]

I have a 6-8 rough draft on obesity due on Thursday!
i haven't even read

every time i read anything
someone motivate me!
every time i try and read it goes in one ea and out the other!

You can lead a horse to water but can't make him drink it.

[Jeddi]

Alright or All right? DOes it matter?

[Arlecchino]

I have a 6-8 rough draft on obesity due on Thursday!
i haven't even read

every time i read anything
someone motivate me!
every time i try and read it goes in one ea and out the other!

Post at least half of it tomorrow or I will ban you for two weeks.

[TheLostSim1718]

Post at least half of it tomorrow or I will ban you for two weeks.

I lol'd

and lol'd at the smiley touch.


its like
POST IT OR SUFFER but let me make it better with a smile

[broonieled]

-1.

i is the square root of -1

therefore i to the power of i

is square root of -1 squared

= -1

i's absolute value is |1| no matter how you look at it... the overall value is still 1.. so 1 times itself is still 1.. doesnt matter whether its negative or positive... so i^i = 1.. and thats how you can prove it^^^ someone correct me if im wrong

lol

[Daffle]

Post at least half of it tomorrow or I will ban you for two weeks.

ok and if i post half of it tomorrow
you get me back in the grene?

[Daffle]

As a member of President Andrew Jackson?s press corps you have seen many different events. You have now been assigned to write a feature story about the Trail of Tears that followed the Cherokee removal from their land. Your story is to be dated in late 1838 or early 1839.

[Davidthefat]

Help me on the collision... The mouse collision works without the map collision code in but the map collision messes everything up...

#include <allegro.h>

int x = 10;
int y = 10;

bool collision = false;
int bass_bb_left = 0;
int bass_bb_top = 0;
int bass_bb_right = 0;
int bass_bb_bottom = 0;

int m_bb_left = 0;
int m_bb_top = 0;
int m_bb_right = 0;
int m_bb_bottom = 0;

int cmap_left[12][16];
int cmap_top[12][16];
int cmap_right[12][16];
int cmap_bottom[12][16];

int map[12][16] = {{1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1},
                   {1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1},
                   {1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1},
                   {1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1},
                   {1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1},
                   {1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1},
                   {1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1},
                   {2,1,1,1,1,1,1,1,1,1,2,2,2,2,2,2},
                   {1,1,1,1,1,1,1,1,1,1,2,3,3,3,3,3},
                   {1,1,1,1,1,1,1,1,1,1,2,3,3,3,3,4},
                   {1,1,1,1,1,1,1,1,1,1,2,3,3,3,3,3},
                   {1,1,1,1,1,1,1,1,1,1,2,3,3,3,3,3}};



BITMAP *my_pic = NULL; 

int startX[18] = {3,19,51,94,143,186,220,255,290,4,52,84,127,189,236,280,315,349};
int startY[18] = {0,0,0,0,0,12,12,12,12,69,69,69,69,69,69,69,69,69};
int endX[18] = {14,27,39,45,39,31,31,31,41,39,29,33,42,45,40,28,32,41};
int endY[18] = {64,64,64,64,64,52,52,52,52,48,48,48,48,48,48,48,48,48};
int frame = 0;

void setup();
void game();
void init();
void deinit();

int main() 
{

    setup();

}
END_OF_MAIN()
void setup()
{
     init();

     game();

	deinit();

}
void game()
{
     my_pic = load_bitmap("bass1.bmp", NULL); 
BITMAP *Buffer = create_bitmap( 640, 480);
if(Buffer == NULL)
{
       set_gfx_mode(GFX_TEXT,0,0,0,0);
         allegro_message("Could not create buffer!");
           exit(EXIT_FAILURE);
}

     

     	while (!key[KEY_ESC]) 
         {

		clear_keybuf();
        clear_bitmap(Buffer);         
        acquire_screen();

                
                //update bounding Boxes
        bass_bb_left = x;
        bass_bb_top = y;
        bass_bb_right = bass_bb_left + endX[frame];
        bass_bb_bottom = bass_bb_top + endY[frame];
        m_bb_left = mouse_x;
        m_bb_top = mouse_y;
        m_bb_right = m_bb_left + endX[frame];
        m_bb_bottom = m_bb_top + endY[frame];
        
        
        for (int i = 0; i <= 11; i++)
        {
     
        for( int t = 0; t <= 15; t++)
        {
            
            if( map[i][t] == 1)
            {
                 rectfill( Buffer, t * 40, i * 40, (t + 1) * 40, (i + 1) * 440, makecol( 128, 255, 255));
                 
                 cmap_left[i][t] = 0;
            cmap_top[i][t] = 0;
            cmap_right[i][t] = 0;
            cmap_bottom[i][t] = 0;
            
            }
            else if( map[i][t] == 2) 
            {
                 rectfill( Buffer, t * 40, i * 40, (t + 1) * 40, (i + 1) * 40, makecol( 255, 128, 0));
                 
                 cmap_left[i][t] = t * 40;
            cmap_top[i][t] = i * 40;
            cmap_right[i][t] = (t + 1) * 40;
            cmap_bottom[i][t] = (i + 1) * 40;
            
            }
            else if( map[i][t] == 3) 
            {
                 rectfill( Buffer, t * 40, i * 40, (t + 1) * 40, (i + 1) * 40, makecol( 255, 0, 0));
                 
                 cmap_left[i][t] = t * 40;
            cmap_top[i][t] = i * 40;
            cmap_right[i][t] = (t + 1) * 40;
            cmap_bottom[i][t] = (i + 1) * 40;
            
            }
            else if( map[i][t] == 4) 
            {
                 rectfill( Buffer, t * 40, i * 40, (t + 1) * 40, (i + 1) * 40, makecol( 0, 0, 0));
                 
                 cmap_left[i][t] = 0;
            cmap_top[i][t] = 0;
            cmap_right[i][t] = 0;
            cmap_bottom[i][t] = 0;
            
                 }
            
            
           }       
        
    }  
       collision = true;
        
        if(bass_bb_bottom < m_bb_top)
        {
        collision = false;
        }
        
        else if(bass_bb_top > m_bb_bottom)
        {
        collision = false;
        }
        
        else if(bass_bb_right < m_bb_left)
        {
        collision = false;
        }
        
        else if(bass_bb_left > m_bb_right)
        {
        collision = false;
        }
       
        //Map Collision
        for (int r = 0; r <= 11; r++){
     
        for( int c = 0; c <= 15; c++){
             if(bass_bb_bottom < cmap_top[r][c] && cmap_top[r][c] != 0)
        {
        collision = false;
        }
        
        else if(bass_bb_top > cmap_bottom[r][c] && cmap_bottom[r][c] != 0)
        {
        collision = false;
        }
        
        else if(bass_bb_right < cmap_left[r][c] && cmap_left[r][c] != 0)
        {
        collision = false;
        }
        
        else if(bass_bb_left > cmap_right[r][c] && cmap_right[r][c] != 0)
        {
        collision = false;
        }
        }
        }
        

        
        
        //get keyboard
        if (key[KEY_UP]) 
        {
             y -= 3;
             if(frame >= 9 && frame <= 16)
             {
             frame ++;
             }
             else if(frame < 9)
             {
                  frame = 9;
             }
             else if (frame >= 17)
        {
        frame = 9;
        }
        }        
        else if (key[KEY_DOWN]) 
        {
             y += 3;   

             if(frame >= 9 && frame <= 16)
             {
             frame ++;
             }
             else if(frame < 9)
             {
                  frame = 9;
             }
             else if (frame >= 17)
        {
        frame = 9;
        }
        }
        else if (key[KEY_RIGHT])
        {
             x += 3;

             if(frame >= 9 && frame <= 16)
             {
             frame ++;
             }
             else if(frame < 9)
             {
                  frame = 9;
             }
             else if (frame >= 17)
        {
        frame = 9;
        }
        }
        else if (key[KEY_LEFT]) 
        {
             
             x -= 3;

             if(frame >= 9 && frame <= 16)
             {
             frame ++;
             }
             else if(frame < 9)
             {
                  frame = 9;
             }
             else if (frame >= 17)
        {
        frame = 9;
        }
        }
        else 
        {
             frame = 7;
        }
        if(collision == true)
        {
              textout_ex( Buffer, font, "Collision!", 0, 0, makecol( 0, 0, 255), makecol( 0, 0, 0) );
              frame = 5;
              

        }
        

        //sprite
        masked_blit(my_pic, Buffer, startX[frame],startY[frame],x,y,endX[frame],endY[frame]);
        masked_blit(my_pic, Buffer, startX[frame],startY[frame],mouse_x,mouse_y,endX[frame],endY[frame]);
        
        line(Buffer, bass_bb_left, bass_bb_top, bass_bb_right, bass_bb_top, makecol(255,0,0));
        line(Buffer, bass_bb_left, bass_bb_bottom, bass_bb_right, bass_bb_bottom, makecol(255,0,0));
        line(Buffer, bass_bb_left, bass_bb_top, bass_bb_left, bass_bb_bottom, makecol(255,0,0));
        line(Buffer, bass_bb_right, bass_bb_top, bass_bb_right, bass_bb_bottom, makecol(255,0,0));

        line(Buffer, m_bb_left, m_bb_top, m_bb_right, m_bb_top, makecol(255,0,0));
        line(Buffer, m_bb_left, m_bb_bottom, m_bb_right, m_bb_bottom, makecol(255,0,0));
        line(Buffer, m_bb_left, m_bb_top, m_bb_left, m_bb_bottom, makecol(255,0,0));
        line(Buffer, m_bb_right, m_bb_top, m_bb_right, m_bb_bottom, makecol(255,0,0));
        
        for (int r = 0; r <= 11; r++)
        {
     
        for( int c = 0; c <= 15; c++)
        {
            
             line(Buffer, cmap_left[r][c], cmap_top[r][c], cmap_right[r][c], cmap_top[r][c], makecol(255,0,0));
        line(Buffer, cmap_left[r][c], cmap_bottom[r][c], cmap_right[r][c], cmap_bottom[r][c], makecol(255,0,0));
        line(Buffer, cmap_left[r][c], cmap_top[r][c], cmap_left[r][c], cmap_bottom[r][c], makecol(255,0,0));
        line(Buffer, cmap_right[r][c], cmap_top[r][c], cmap_right[r][c], cmap_bottom[r][c], makecol(255,0,0));
        
        }
        }
        if (collision == false)
        {
        y += 10;

        }
        if (y >= 480)
        {
              y =0;
        }
        
        
        draw_sprite( screen, Buffer, 0, 0);

        release_screen();
        
        rest(50);


        }
}
void init() {
	int depth, res;
	allegro_init();
	depth = desktop_color_depth();
	if (depth == 0) depth = 32;
	set_color_depth(depth);
	res = set_gfx_mode(GFX_AUTODETECT_WINDOWED, 640, 480, 0, 0);
	if (res != 0) {
		allegro_message(allegro_error);
		exit(-1);
	}

	install_timer();
	install_keyboard();
	install_mouse();

}

void deinit() {
	clear_keybuf();

}

[B-Neva]

jesus david, stop coding this **** LOL ur 15, this is not allowed!

[O.B.]

If anybody has any questions on economics I can probably help. I study business economics at Tilburg University.

[samsuperjew]

This is as relevant as you make it. Skill is not only using the appropriate tool at the appropriate time, but selecting the right tool for the task. The more you have to select from . . .

Most of what you are able to take at this time will not be directly relevant. Honestly, many first year programs, at least in the US, are remarkably generic. You could pick up a used ex phys text and go through it on your own, really. As well as doing other things to increase your base level of knowledge.

thanks


luckily for now, i managed to find a program that keeps me with kids all day, then for 5 hours a day, it splits everyone up to go intern at different countries around the city (program is in a different state)....... they are seeing if there are any college or pro football or weightlifting coaches around with an open spot

[andthenithitme]

Some basic chem stuff, don't need to know answers just how to do them.
What volume will the following quantities of gas occupy at STP
1.28.0g of N2
2. 60.0 g of CO2
Determine the number of grams in each of the quantties below
1. 2.5 moles NaCl= g NaCl


1. How many moles of magnesium are in 3.01 x 10 22 atoms of magnesium
2. How many molecules are in 4.00 mol of glucose, C6H12O6
3. How many atoms are in 7.99 moles of Lithium?

[Joel1990]

For the Ancient History brahs here are some notes that i did for my research paper enjoy, should help you guys

[iamme098]

Some basic chem stuff, don't need to know answers just how to do them.
What volume will the following quantities of gas occupy at STP
1.28.0g of N2
2. 60.0 g of CO2
Determine the number of grams in each of the quantties below
1. 2.5 moles NaCl= g NaCl


1. How many moles of magnesium are in 3.01 x 10 22 atoms of magnesium
2. How many molecules are in 4.00 mol of glucose, C6H12O6
3. How many atoms are in 7.99 moles of Lithium?

For the first two

PV = nRT is your friend.

P= pressure in atm
V= volume in L
n= number of moles of gas
R= universal gas constant
T= temp in K

STP is 1 atm pressure 0* C/273.15 K

find the mol of each by taking the number of grams like you have and dividing by the molar mass. you can find it on wikipedia or a periodic table or something

then just plug it in and solve for V.


to determine the grams of the next one, you gotta find the molar mass of NaCl. which is the molar mass of Na + molar mass Cl. multiply it by 2.5 (the number of moles you have)


1. How many moles of magnesium are in 3.01 x 10 22 atoms of magnesium
Avogadro's number is 6.02 x 10^23 i think. That's the number of atoms in 1 mol of any substance. so just divide the atoms you have by avogadro's number.


2. How many molecules are in 4.00 mol of glucose, C6H12O6
this tries to make things look more complicated than they are. using the same concept as above, a mole of glucose is gonna have 6.02 x 10^23 molecules in it. just multiply by 4.
3. How many atoms are in 7.99 moles of Lithium?
moles of lithium / avogadro's #


check avogadro's number in google or something i'm pretty sure that's right but not 100%

[Deadlift_10KG]

Guys, I need to make some sort of visual representation of this article:

http://ezinearticles.com/?Internatio...les&id=3110099

It's got to be around half a page. I need help in making the visual, I already have the info that needs to be on it.

Edit: I got it now

[FatKidsOnMopeds]

-1.

i is the square root of -1

therefore i to the power of i

is square root of -1 squared

= -1

i's absolute value is |1| no matter how you look at it... the overall value is still 1.. so 1 times itself is still 1.. doesnt matter whether its negative or positive... so i^i = 1.. and thats how you can prove it^^^ someone correct me if im wrong

All of this is wrong

i^i = e ^ (-pi/2)

For a quick proof, use what you know about basic exponential and logarithmic expansions and euler's identity. A few easy comments and modifications will make it a rigorous proof. But I'm guessing noone cares about the proof...so that's what the answer is. It is right.

[stronguy91]

what are the positive and negative effects of the media on american democracy?

[iamme098]

If anybody has any questions on economics I can probably help. I study business economics at Tilburg University.

Same goes for me with Chemistry. I'm a junior majoring in it with a minor in biochem.

[stronguy91]

what are the positive and negative effects of the media on american democracy?

bump...i really need this for tomorrow