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Old 11-14-2007, 10:12 PM   #1
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Question Physics help...??

Anyone good a physics?

The problem is: vs^2=vi^2 + 2ad

Rearrange and solve for d.

the^ in there is squared or to the power of 2.
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~D~

Last edited by Dnyc99; 11-14-2007 at 10:14 PM.
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Old 11-14-2007, 10:13 PM   #2
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vv^2
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Old 11-14-2007, 10:14 PM   #3
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edit: noodz?
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Old 11-14-2007, 10:14 PM   #4
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vv^2
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Old 11-14-2007, 10:15 PM   #5
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D= (Vs^2 - Vi^2)/2a

Edit: I probably read it wrong.
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Old 11-14-2007, 10:17 PM   #6
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Quote:
Originally Posted by V1984 View Post
D= (Vs^2 - Vi^2)/2a

Edit: I probably read it wrong.
Awesome thanks!!

Reps for ya.

~D~
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Old 11-14-2007, 10:37 PM   #7
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Quote:
Originally Posted by V1984 View Post
D= (Vs^2 - Vi^2)/2a

Edit: I probably read it wrong.
btw: Darkfalcon is going to rep you later too.

~D~
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Old 11-14-2007, 10:50 PM   #8
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Quote:
Originally Posted by Dnyc99 View Post
Anyone good a physics?

The problem is: vs^2=vi^2 + 2ad

Rearrange and solve for d.

the^ in there is squared or to the power of 2.
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vs^2=vi^2=2ad

vi^2-vs^2=2ad


Final answer:

d = vi^2-vs^2
.......... 2a
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Old 11-14-2007, 10:52 PM   #9
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Thats pretty basic algebra. If you can't do that maybe you shouldn't be in physics.
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Old 11-14-2007, 10:52 PM   #10
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Thats pretty basic algebra. If you can't do that maybe you shouldn't be in physics.
Agreed.....
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Old 11-14-2007, 10:54 PM   #11
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Quote:
Originally Posted by khaderama View Post
vs^2=vi^2=2ad

vi^2-vs^2=2ad


Final answer:

d = vi^2-vs^2
.......... 2a
When you move the vi^2 over, it becomes negative.
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Old 11-14-2007, 10:57 PM   #12
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When you move the vi^2 over, it becomes negative.
Yes. So does 2ad, so you mulitply both sides by -1 and end up with that.
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Old 11-14-2007, 11:00 PM   #13
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Quote:
Originally Posted by khaderama View Post
Yes. So does 2ad, so you mulitply both sides by -1 and end up with that.
We're dividing both sides by 2a, not subtracting. I'm pretty sure I'm correct ... it's late and maybe it's too obvious and I'm missing something.
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Old 11-14-2007, 11:13 PM   #14
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Quote:
Originally Posted by V1984 View Post
We're dividing both sides by 2a, not subtracting. I'm pretty sure I'm correct ... it's late and maybe it's too obvious and I'm missing something.
Nevermind I see what I did wrong. I thought it was - 2ad not plus 2ad. My bad.
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