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What is the integral of 7^x?

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e^What the fuk is this Wolfram stfu and go do some homework
+ C

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Really basic stuff 7^x/ln7 + C

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Dude, it's (7^x)/(ln7) + C
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Originally Posted by PastorofMupets
Originally Posted by Gmanju
Really basic stuff 7^x/ln7 + C
Originally Posted by Danthesaxman
Dude, it's (7^x)/(ln7) + C
How do I get that?

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well just think what is the derivative of 7^x? (7^x)(ln7)
if you know the answer to that, you can intuitively come to the answer.

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Originally Posted by thercias
well just think what is the derivative of 7^x? (7^x)(ln7)
if you know the answer to that, you can intuitively come to the answer.
I don't know that. Never seen a problem like this and there's none like it in the textbook

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Originally Posted by retiredrunner
e^What the fuk is this Wolfram stfu and go do some homework
+ C
hahahaha I frequently forgot the +C

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Originally Posted by PastorofMupets
i think I could learn Arabic before this chit

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Originally Posted by Danthesaxman
Dude, it's (7^x)/(ln7) + C
this
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dont worry brahs I have arrived:
let y = 7^(x) = e^(ln(7^x)) = e^(xln7)
so integral of 7^x = integral of e^(xln(7). you can integrate that very easily.
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Originally Posted by CollegeBoy12
HAHAHAHAHHAHAHA potato!!!!
This thread reminds me of my college calculus professor would look at us like retards and make fun of us if we asked her questions.

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Originally Posted by Lee72
I don't know that. Never seen a problem like this and there's none like it in the textbook
I already told you the answer. derivative of a^x = a^xlna. Think backwards when doing integral problems. "What answer, when taken the derivative, gives me 7^x?" Well, the derivative of 7^x/ln7 = 7^x*ln7/ln7 = 7^x.

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Originally Posted by thercias
well just think what is the derivative of 7^x? (7^x)(ln7)
if you know the answer to that, you can intuitively come to the answer.
This. Because remember, the made up (but somewhat useful) term "antiderivative" implies that an integral is the opposite of the derivative.
You know the derivative of 7^x = 7^x * ln7
Therefore, the integral of 7^x is the reverse of this process :: ask yourself, "The derivative of what value = 7^x?"
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Originally Posted by diffrentiable
dont worry brahs I have arrived:
let y = 7^(x) = e^(ln(7^x)) = e^(xln7)
so integral of 7^x = integral of e^(xln(7). you can integrate that very easily.
Got it, thanks brah. x^e is also giving me trouble

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Originally Posted by Lee72
Got it, thanks brah. x^e is also giving me trouble
notsureifsrs
e is a constant, bro.
External motivation is fantastic, but at the end of the day it is inevitably temporary.
Inexorable longterm motivation must come from within.

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Originally Posted by Lee72
Got it, thanks brah. x^e is also giving me trouble
do you know the integral of x^2. If so, why do you have trouble with x^e?

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Originally Posted by Danthesaxman
notsureifsrs
e is a constant, bro.
I believe it is (x^(e+1))/(e+1)? I'm just not sure about doing it like that

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Originally Posted by Lee72
I believe it is (x^(e+1))/(e+1)? I'm just not sure about doing it like that
Exactly. + C
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Approximately x^gotoclass

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Another one...
xe^x^2
I got the answer with wolfram but I need to know how to do it

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Originally Posted by Lee72
Another one...
xe^x^2
I got the answer with wolfram but I need to know how to do it
Integrate it by parts. I'm not going to do it for you.
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Originally Posted by Lee72
rule you just have to remember i think

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Originally Posted by PlatonicIdeal
Integrate it by parts. I'm not going to do it for you.
F*ck we didn't get to integration by parts... This might be one of the questions I don't have to do

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Isolate x and e^(x)^2, use the power rule. When you differentiate each of the two terms you gotta use the chain rule and u substitution for the e^(x)^2 component.
edit: my bad thought differentiation, just use u substitution.
Last edited by Motedust; 06162013 at 12:12 AM.
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