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  1. #1
    Registered User Lee72's Avatar
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    What is the integral of 7^x?

    ???
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  2. #2
    being old rules retiredrunner's Avatar
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    e^What the fuk is this Wolfram stfu and go do some homework










    + C
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    ronceiro
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    Forever 'mirin

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  5. #5
    I can confirm I am Gainz Gmanju's Avatar
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    Really basic stuff 7^x/ln7 + C
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  6. #6
    1 cheeky kunt m8 CollegeBoy12's Avatar
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    potato?
    avoids his italian grandmas house like the plague when on a cut crew
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  7. #7
    Registered User Danthesaxman's Avatar
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    Dude, it's (7^x)/(ln7) + C
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  8. #8
    Impossible is Nothing BrandonMag's Avatar
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    3^lol
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    ((1) / (n+1)) x ^ (n+1)
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  10. #10
    Registered User Lee72's Avatar
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    Originally Posted by PastorofMupets View Post
    Originally Posted by Gmanju View Post
    Really basic stuff 7^x/ln7 + C
    Originally Posted by Danthesaxman View Post
    Dude, it's (7^x)/(ln7) + C
    How do I get that?
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  11. #11
    Registered User thercias's Avatar
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    well just think what is the derivative of 7^x? (7^x)(ln7)
    if you know the answer to that, you can intuitively come to the answer.
    Chaldean/Assyrian crew
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  12. #12
    Registered User Lee72's Avatar
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    Originally Posted by thercias View Post
    well just think what is the derivative of 7^x? (7^x)(ln7)
    if you know the answer to that, you can intuitively come to the answer.
    I don't know that. Never seen a problem like this and there's none like it in the textbook
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  13. #13
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    Originally Posted by retiredrunner View Post
    e^What the fuk is this Wolfram stfu and go do some homework










    + C
    hahahaha I frequently forgot the +C
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  14. #14
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    Originally Posted by PastorofMupets View Post
    i think I could learn Arabic before this chit
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  15. #15
    beast from da middle east RandTheRand's Avatar
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    Originally Posted by Danthesaxman View Post
    Dude, it's (7^x)/(ln7) + C
    this
    kick the f*** back
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  16. #16
    cheekiest brah on misc diffrentiable's Avatar
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    dont worry brahs I have arrived:
    let y = 7^(x) = e^(ln(7^x)) = e^(xln7)
    so integral of 7^x = integral of e^(xln(7). you can integrate that very easily.
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    Originally Posted by CollegeBoy12 View Post
    potato?
    HAHAHAHAHHAHAHA potato!!!!

    This thread reminds me of my college calculus professor would look at us like retards and make fun of us if we asked her questions.
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  18. #18
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    Originally Posted by Lee72 View Post
    I don't know that. Never seen a problem like this and there's none like it in the textbook
    I already told you the answer. derivative of a^x = a^xlna. Think backwards when doing integral problems. "What answer, when taken the derivative, gives me 7^x?" Well, the derivative of 7^x/ln7 = 7^x*ln7/ln7 = 7^x.
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  19. #19
    Registered User Danthesaxman's Avatar
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    Originally Posted by thercias View Post
    well just think what is the derivative of 7^x? (7^x)(ln7)
    if you know the answer to that, you can intuitively come to the answer.
    This. Because remember, the made up (but somewhat useful) term "antiderivative" implies that an integral is the opposite of the derivative.

    You know the derivative of 7^x = 7^x * ln7
    Therefore, the integral of 7^x is the reverse of this process :: ask yourself, "The derivative of what value = 7^x?"
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  20. #20
    Registered User Lee72's Avatar
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    Originally Posted by diffrentiable View Post
    dont worry brahs I have arrived:
    let y = 7^(x) = e^(ln(7^x)) = e^(xln7)
    so integral of 7^x = integral of e^(xln(7). you can integrate that very easily.
    Got it, thanks brah. x^e is also giving me trouble
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  21. #21
    Registered User Danthesaxman's Avatar
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    Originally Posted by Lee72 View Post
    Got it, thanks brah. x^e is also giving me trouble
    notsureifsrs

    e is a constant, bro.
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  22. #22
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    Originally Posted by Lee72 View Post
    Got it, thanks brah. x^e is also giving me trouble
    do you know the integral of x^2. If so, why do you have trouble with x^e?
    Chaldean/Assyrian crew
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  23. #23
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    Originally Posted by Danthesaxman View Post
    notsureifsrs

    e is a constant, bro.
    I believe it is (x^(e+1))/(e+1)? I'm just not sure about doing it like that
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  24. #24
    Registered User Danthesaxman's Avatar
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    Originally Posted by Lee72 View Post
    I believe it is (x^(e+1))/(e+1)? I'm just not sure about doing it like that
    Exactly. + C
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  25. #25
    Long Arms of Peace Gilmanjo's Avatar
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    Approximately x^gotoclass
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  26. #26
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    Another one...

    xe^-x^2

    I got the answer with wolfram but I need to know how to do it
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  27. #27
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    Originally Posted by Lee72 View Post
    Another one...

    xe^-x^2

    I got the answer with wolfram but I need to know how to do it
    Integrate it by parts. I'm not going to do it for you.
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    Originally Posted by Lee72 View Post
    How do I get that?
    rule you just have to remember i think
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    Originally Posted by PlatonicIdeal View Post
    Integrate it by parts. I'm not going to do it for you.
    F*ck we didn't get to integration by parts... This might be one of the questions I don't have to do
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    Isolate x and e^(-x)^2, use the power rule. When you differentiate each of the two terms you gotta use the chain rule and u substitution for the e^(-x)^2 component.

    edit: my bad thought differentiation, just use u substitution.
    Last edited by Motedust; 06-16-2013 at 12:12 AM.
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