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1. ## 0.99999... = 1

If you think otherwise you are a moran

2. well duh. It's only been proven like 40 different ways

3. in...im fuked up but im in

4. I agree with this statement

5. 0.99999999999999999 = 0.99999999999999999.

6. why?

7. Originally Posted by Crenity
0.99999999999999999 = 0.99999999999999999.

0.99999999999999999 != 0.999... (recurring)

0.999... = 0.999... = 1

Originally Posted by everglide123
why?
x = 0.999...
10x = 9.999...
10x-x = 9.999... - 0.999...
9x = 9
x = 1

8. and here we go

9. lol

10. explain how a number starting with 0 can equal 1!?!!?!! zomg rawr

11. it's 288

12. If .9999999999 = 1

then...

.0000000000...01 = 0

But

.0000000000...01 + .99999999999 = 1 not .999999999999

Ergo...

8======D ~~~~~ O-:

13. so then what does 0.9999999999999999999999999999..... + 349 =?

14. Originally Posted by TheCurator
0.99999999999999999 != 0.999... (recurring)

0.999... = 0.999... = 1

x = 0.999...
10x = 9.999...
10x-x = 9.999... - 0.999...
9x = 9
x = 1
not exactly a proper proof, saying 10x=9.999.... assumes already that .999... equals 1, that's why the math works out as it does. But, the point is still correct, .999... does equal one but for a different reason.

15. Since:

1/3 = .333333...
2/3 = .666666...

1/3 + 2/3 = .999999... = 1.

erryone go to bed

16. Originally Posted by everglide123
hmm that's weird, I guess your right but it's sort of a paradox.

0.999 grams of protein =/= 1 gram of protein. Not the same amount of molecules/protons/quarks.
0.999 is not the same thing as 0.999...

Originally Posted by blooeyez
If .9999999999 = 1

then...

.0000000000...01 = 0

But

.0000000000...01 + .99999999999 = 1 not .999999999999

Ergo...

8======D ~~~~~ O-:

0.000.... 001 =/= 0

8====D---()8p

Originally Posted by JustDuIt
so then what does 0.9999999999999999999999999999..... + 349 =?
bout tree fiddy

17. OP i am disappoint at your poor attempt at rehashing an old argument for no reason but your own ego

18. Inb4 misc has a math war all over again..

19. Originally Posted by blooeyez
If .9999999999 = 1

then...

.0000000000...01 = 0

But

.0000000000...01 + .99999999999 = 1 not .999999999999

Ergo...

8======D ~~~~~ O-:
You can't put .01 after an infinite, that makes no sense at all. You need to define a finite amount of numericals before the 1.

Dumbass

Also OP is 100% correct. Anyone saying otherwise is a retard and needs to be put to sleep so they cannot reproduce, infecting this earth with their retarded genes

not exactly a proper proof, saying 10x=9.999.... assumes already that .999... equals 1, that's why the math works out as it does. But, the point is still correct, .999... does equal one but for a different reason.
No, 10x = 9.999... does not assume that 0.999... equals 1. What does 10 times 0.999... equal?

21. Originally Posted by TheCurator
No, 10x = 9.999... does not assume that 0.999... equals 1. What does 10 times 0.999... equal?
Using algebra on an infinite series is just something I don't like to do. Infinity is not subject to the laws of arithmetic, you can "prove" anything you want by making that mistake. Not to say I disagree, I just wouldn't use that as a proof. I completely do agree .999...=1.

22. Originally Posted by TheCurator
If you think otherwise you are a moran
Moran

Moran

23. I don't see how that is possible....saying 1/3 is EXACTLY .333.... is not true to me... 1/3 is 3/9

.33333.... x 3 =/= 100

Algebra proof

(Moved from above to ease editing)

Another kind of proof adapts to any repeating decimal. When a fraction in decimal notation is multiplied by 10, the digits do not change but the decimal separator moves one place to the right. Thus 10 × 0.9999… equals 9.9999…, which is 9 more than the original number. To see this, consider that subtracting 0.9999... from 9.9999… can proceed digit by digit; the result is 9 − 9, which is 0, in each of the digits after the decimal separator. But trailing zeros do not change a number, so the difference is exactly 9. The final step uses algebra. Let the decimal number in question, 0.9999…, be called c. Then 10c − c = 9. This is the same as 9c = 9. Dividing both sides by 9 completes the proof: c = 1."

This is not true because if c were a variably then it may be replaced by any number. For exaple, if c=5 then 10(5) -5 would equal 9, which it clearly does not. That leaves c to be a constant, which in this case c will aways equal .9 infinity. Although 10(.9999...)-(.9999...) does equal 9, the second part of the equation does not equal 9. When you substitute c is the equation 9 *(.9999...)= 9.9999... and not 9.

Using algebra on an infinite series is just something I don't like to do. Infinity is not subject to the laws of arithmetic, you can "prove" anything you want by making that mistake. Not to say I disagree, I just wouldn't use that as a proof. I completely do agree .999...=1.
why dont u say that to my face fuker not online see what happens

25. Originally Posted by Clifford-James
Moran

Moran

In b4 ten pages of people not realizing the significance of "..."

Edit: 288. Anteater. JTF2 > SAS. USA > Britain. blasting music from your car, is it alpha?

26. Originally Posted by TheCurator
why dont u say that to my face fuker not online see what happens
Gladly, I will then prove to you why you can't use laws of arithmetic on infinity. Should be an enlightening encounter.

27. show me when .999... turns to 1 and i'll believe you.

and lol at you "disproving" most people because they forgot to put ...

28. Since when the **** do you use "..." in mathematics?

it's 0.(9) = 1

29. ya... just like how .33333333..... = 1/3

same logic. it's not hard to understand. lol.

30. The proper thread title should be:

Mathematically 0.(9) CAN = 1

Saying it any other way doesn't really work.

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