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  1. #5971
    But it was only fantasy SCAR-H's Avatar
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    Originally Posted by MiscMathematician View Post
    Im not sure what parts (a) and (b) represent in number 1. In part (b), are you concluding anything? All proofs should end with a clear conclusion drawn from what you have done
    1a) Prove that if a subset {u_1, ... , u_p} is linearly dependent in V, then the set of coordinate vectors {[u_1]_B, ... , [u_p]_B} is linearly dependent in R^n.

    1b) Prove that if the set of coordinate vectors {[u_1]_B, ... , [u_p]_B} is linearly dependent in R^n, then the subset {u_1, ... , u_p} is linearly dependent in V.
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  2. #5972
    But it was only fantasy SCAR-H's Avatar
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    Originally Posted by MiscMathematician View Post
    The manipulations you have done are file. Maybe a little more explanation? For example, you seem to be using [u]_B=[v]_B implies u=v. Is that covered in "1-1"?
    For some x,y in V

    let [x]_B = [y]_B

    Given that x -> [x]_B is a 1-1 linear transformation from V onto R^n, isn't it true that x = y?
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  3. #5973
    But it was only fantasy SCAR-H's Avatar
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    Originally Posted by MiscMathematician View Post
    yes, of course it's true. But i dont know what you're working with, i thought 1-1 referred to a theorem. if you know about 1-1 linear transformations, then you can directly state

    Assume c_1[u_1]_B+...+c_k[u_k]_B =[0]_B

    then

    [c_1u_1+...+c_ku_k]_B = c_1[u_1]_B+...+c_k[u_k]_B = [0]_B

    so

    c_1u_1+...+c_ku_k = 0.

    This proves (b) it by the definition of linear dependence, and doesn't need any division, solving for one if the u_i's, etc.
    luls yeah, that's exactly what he did when I went to his office hours. Thanks again.
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  4. #5974
    Registered User iDontExistHere's Avatar
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    I need some guidance.

    A= the set of all positive integers R = {(x,y)} | x and y are prime numbers:
    Reflexive:
    Symmetric:
    Transitive:

    With this question I'm confused: Could I use (1,1) as a counter example because 1 Is a positive integer in A. OR do I just have to use STRICTLY prime numbers? I'm kinda confused on the logic behind the question. I partially understand what to do & how to do it.
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  5. #5975
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    Originally Posted by iDontExistHere View Post
    I need some guidance.

    A= the set of all positive integers R = {(x,y)} | x and y are prime numbers:
    Reflexive:
    Symmetric:
    Transitive:

    With this question I'm confused: Could I use (1,1) as a counter example because 1 Is a positive integer in A. OR do I just have to use STRICTLY prime numbers? I'm kinda confused on the logic behind the question. I partially understand what to do & how to do it.
    x and y both have to be prime numbers.
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  6. #5976
    Registered User iDontExistHere's Avatar
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    Originally Posted by charity4thepoor View Post
    x and y both have to be prime numbers.
    I thought for reflexive a counter example could be (1,1) since it is on the set of positive integers.
    (reflexive deals with the entire set not just prime numbers right?)
    So it wouldn't be reflexive.
    It would be symmetric tho because for all (x,y) *strictly prime on the set of positive integers* (y,x) would be prime
    Also it would be transitive because for (x,y,z) all prime int. (x,z) would also be prime.
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  7. #5977
    Get Money ctownballer04's Avatar
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    Originally Posted by iDontExistHere View Post
    I thought for reflexive a counter example could be (1,1) since it is on the set of positive integers.
    (reflexive deals with the entire set not just prime numbers right?)
    So it wouldn't be reflexive.
    It would be symmetric tho because for all (x,y) *strictly prime on the set of positive integers* (y,x) would be prime
    Also it would be transitive because for (x,y,z) all prime int. (x,z) would also be prime.
    Maybe you are misunderstanding the question?

    "R={(x,y)} | x and y are prime numbers}:"

    In words this says, R equals the set of ordered pairs, (x,y), such that x and y are both prime numbers.

    By definition, 1 is not a prime number, thus your counterexample doesn't make sense.
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  8. #5978
    Registered User iDontExistHere's Avatar
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    Originally Posted by ctownballer04 View Post
    Maybe you are misunderstanding the question?

    "R={(x,y)} | x and y are prime numbers}:"

    In words this says, R equals the set of ordered pairs, (x,y), such that x and y are both prime numbers.

    By definition, 1 is not a prime number, thus your counterexample doesn't make sense.
    You're right. I was thinking reflexive dealt with ALL positive integers. not just prime numbers. So what is the purpose of the " A = all positive integers"?
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  9. #5979
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    Originally Posted by MiscMathematician View Post
    I was helping this cute girl with graphing hyperbolas today.

    You know how you draw that imaginary box, where the asymptotes pass through it diagonally?

    I kept saying stuff like "where is your box going to be?", "thats a nice box", "show me your box", "what does your box look like?" etc. She laughed erry time.

    And then it hit me.
    rofl
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  10. #5980
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    Originally Posted by MiscMathematician View Post
    I was helping this cute girl with graphing hyperbolas today.

    You know how you draw that imaginary box, where the asymptotes pass through it diagonally?

    I kept saying stuff like "where is your box going to be?", "thats a nice box", "show me your box", "what does your box look like?" etc. She laughed erry time.

    And then it hit me.
    You just confirmed yourself to be a miscer and mathematician in one post.
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  11. #5981
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    Originally Posted by MiscMathematician View Post
    I was helping this cute girl with graphing hyperbolas today.

    You know how you draw that imaginary box, where the asymptotes pass through it diagonally?

    I kept saying stuff like "where is your box going to be?", "thats a nice box", "show me your box", "what does your box look like?" etc. She laughed erry time.

    And then it hit me.
    lmfao. you da GAWD
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  12. #5982
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    Originally Posted by MiscMathematician View Post
    I was helping this cute girl with graphing hyperbolas today.

    You know how you draw that imaginary box, where the asymptotes pass through it diagonally?

    I kept saying stuff like "where is your box going to be?", "thats a nice box", "show me your box", "what does your box look like?" etc. She laughed erry time.

    And then it hit me.
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  13. #5983
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    Originally Posted by MiscMathematician View Post
    I was helping this cute girl with graphing hyperbolas today.

    You know how you draw that imaginary box, where the asymptotes pass through it diagonally?

    I kept saying stuff like "where is your box going to be?", "thats a nice box", "show me your box", "what does your box look like?" etc. She laughed erry time.

    And then it hit me.
    Not a single reeses was thrown that day.






    That being said I should be studying for my 2 day final.
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    Originally Posted by MiscMathematician View Post
    I was helping this cute girl with graphing hyperbolas today.

    You know how you draw that imaginary box, where the asymptotes pass through it diagonally?

    I kept saying stuff like "where is your box going to be?", "thats a nice box", "show me your box", "what does your box look like?" etc. She laughed erry time.

    And then it hit me.
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    Got my exam back from Stats. I got a 100%

    Now we're doing Hypothesis Testing which is apparently the most challenging he says. My professor told me most the students aren't doing so well. We had about 12 drop the class so far. But it doesn't seem difficult so far. I am working on Testing when the Deviation is known. Next is unknown. Then we have an excel project, another short chapter on Linear Regression, then the final
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  16. #5986
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    A Constant and a Function of X are walking down the street.

    The Function of X says "Let's take that alley way and save some time."

    Constant says "No, I see a Derivative down there...he'll turn me to Zero!"

    Function of X says "I'm not scared...he can't turn me to Zero"

    Function of X walks down the alley and right up to the Derivative and says "Hey, I'm Function of X."

    The Derivative responds "Hey I'm d/dt."




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    Last edited by Clydesdale1991; 11-20-2015 at 10:56 AM.
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  17. #5987
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    Originally Posted by Clydesdale1991 View Post
    A Constant and a Function of X are walking down the street.

    The Function of X says "Let's take that alley way and save some time."

    Constant says "No, I see a Derivative down there...he'll turn me to Zero!"

    Function of X says "I'm not scared...he can't turn me to Zero"

    Function of X walks down the alley and right up to the Derivative and says "Hey, I'm Function of X."

    The Derivative responds "Hey I'm d/dt."




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    Every constant may be viewed as a function on any domain (in particular as a function of x), so I think this joke needs rewording
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  18. #5988
    The Lifting Statistician Clydesdale1991's Avatar
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    Originally Posted by YokedBrah View Post
    Every constant may trivially be viewed as a function on any domain (in particular as a function of x), so I think this joke needs rewording
    I think my joke works fine.
    Last edited by Clydesdale1991; 11-20-2015 at 11:32 AM.
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  19. #5989
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    Originally Posted by MiscMathematician View Post
    y=4 certainly is a function.

    I'm an idiot you're right...still think the joke works.

    Been a while....passes the vertical line test.
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  20. #5990
    The Lifting Statistician Clydesdale1991's Avatar
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    Originally Posted by MiscMathematician View Post
    I saw this joke a few years ago as e^x

    Anything works as long as it isn't a function of t.

    Terrible calculus joke...but I like it.
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  21. #5991
    The Lifting Statistician Clydesdale1991's Avatar
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    Originally Posted by MiscMathematician View Post
    it works better with e^x, since he says something like "he can't do sh*t to me"

    Yeah I like it better....been about 5 years since I heard that joke.
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  22. #5992
    The Lifting Statistician Clydesdale1991's Avatar
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    Originally Posted by MiscMathematician View Post
    it works better with e^x, since he says something like "he can't do sh*t to me"
    Twice as good if you use e^2x.....




    Anyone.....anyone.....
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  23. #5993
    Registered User Chesssbrah's Avatar
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    Originally Posted by Clydesdale1991 View Post
    A Constant and a Function of X...

    That guy checkin' in

    Not bad but k = 0 is a constant, so if the constant function were mapping to zero to begin with, why should it worry?
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  24. #5994
    The Lifting Statistician Clydesdale1991's Avatar
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    Originally Posted by Chesssbrah View Post
    That guy checkin' in

    Not bad but k = 0 is a constant, so if the constant function were mapping to zero to begin with, why should it worry?
    Dammit people.......

    Technically you aresholes are right......





    A Constant, whose properties do not include being a function of a variable or the number Zero, and the function e^(x) are walking down the street.

    e^(x) says "Let's take that alley way and save some time."

    Constant says "No, I see a Derivative down there...he'll turn me to Zero!"

    e^(x) says "I'm not scared...he can't do sh%t"

    e^(x) walks down the alley and right up to the Derivative and says "Hey, I'm e^(x)."

    The Derivative responds "Hey I'm d/dt."






    Edit: Not mad at you guys, being corrected means I can fix problems.




    On another note, I was recently helped a ton by my departments systems administrator with some computer problems.

    In response to said help, I decided to make him a T-shirt as a gift. He comes to me sometimes and likes to talk about math.

    Anyone want to see the shirt? If you like cryptography/number theory, you'll like it.
    Last edited by Clydesdale1991; 11-20-2015 at 11:56 AM.
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  25. #5995
    Math question brah killakms's Avatar
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    So is this like a math tutor place? Is it open to all types of math including arithmetic and pre-alg?
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  26. #5996
    The Lifting Statistician Clydesdale1991's Avatar
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    Originally Posted by killakms View Post
    So is this like a math tutor place? Is it open to all types of math including arithmetic and pre-alg?
    I'm sure people are willing to help as long as you are reasonable with the request.

    What's the problem?
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  27. #5997
    Ascended Saiyan YokedBrah's Avatar
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    My favorite math joke:

    What do a topologist and a horny miscer have in common? All they care about are the existence of holes.
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  28. #5998
    The Lifting Statistician Clydesdale1991's Avatar
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    Originally Posted by MiscMathematician View Post
    cryptograhy/algebra/numthy are my fav subjects. lets see it
    Had to cut out most of it so it would fit on the shirt. Also had to pick the shortest quote about helping others, thus the 30 digit prime numbers.

    http://www.customink.com/designs/liy...t-_-viewbutton

    Will take a screen cap in a sec and attach to this post when Iget a chance for those that are wear of links.

    Systems Admins name is Liyun for reference.



    Cut off the encryption process and just showed the process of obtaining the keys and decrypting the message.


    Edit: He's an older guy that likes math so I thought this would be a cool present.
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    Last edited by Clydesdale1991; 11-20-2015 at 12:55 PM.
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  29. #5999
    The Lifting Statistician Clydesdale1991's Avatar
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    Originally Posted by MiscMathematician View Post
    did he catch the mistake?
    Heh?

    Edit: What is das mistake homie?

    Edit2: You can't just say that and not say what the mistake is....lol
    Last edited by Clydesdale1991; 11-20-2015 at 01:08 PM.
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  30. #6000
    The Lifting Statistician Clydesdale1991's Avatar
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    Originally Posted by MiscMathematician View Post
    just messin with you bro. ill check it out later, have to finish up some work
    Damn...almost had a heart attack checking through the math.

    Was like, everything works!!! What's wrong......AHHHHH



    It's a bit busy...but I'm not an artist so I think it looks ok at least.

    I think you'll like it.


    Edit: Also made it an attachment as well, so people who don't want to click a link to another website.

    Attached it on this post as well.
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