The homework help thread...(SERIOUS)

[Ballad]

So how would you apply that to TLA?

I'd assume:

[x(cosx)-sinx]/(x^2) = -[y'(ycosy-siny)]/(y^2)
(y^2)[x(cosx)-sinx]/(x^2) = -[y'(ycosy-siny)]
-[(y^2)[x(cosx)-sinx]/(x^2)]/(ycosy - siny) = y'

?

Edit: but then I just subbed that in to the TLA formula and got 1.70516... still not working out. I must be ****ing something up

[snwbordr008]

As previously stated, I haven't taken calc 1 in quite some time haha. Remind me on TLA? what's the general form

Edit, just looked it up. **** that. pi/180 I assume they want you to assume it's 0 degrees since it's actually 1 degrees. So just estimate about pi/3?

[Ballad]

As previously stated, I haven't taken calc 1 in quite some time haha. Remind me on TLA? what's the general form

Edit, just looked it up. **** that

Basically my thoughts right now

[ANDYMAYNE]

To anyone who has read the book Uncle Tom's Cabin: Please recommend me a strong essay topic pertaining to this book in anyway.

[Csnauk]

Not done Maths since 2009 wut

[JACK550]

Just got this English assignment to review titanic. I know this sounds stupid but I have never seen it, can someone please link me to a website where I can watch/download it? Also, if anyone has any opinions, please share!

Thanks.

[adubas]

any of you *******s heard of "khanacademy.com"? it's much more useful than a bunch of dumbasses on a bodybuilding site.

[DahStoryTella]

any of you *******s heard of "khanacademy.com"? it's much more useful than a bunch of dumbasses on a bodybuilding site.

KhanAcademy, imo, is great but I do disagree with the ''dumbasses'' remark; I've received some very good help in this thread and I am sure that other users have as well.

Anyways, I'm back in school; first year of University and Calculus is one of my classes for this semester so I'll probably be posting here again shortly.

[BandApart]

any of you *******s heard of "khanacademy.com"? it's much more useful than a bunch of dumbasses on a bodybuilding site.

plenty of questions have been adequately answered in this thread, as most of us, while being weight-lifters, are students-college and high school- as well, that have studied these subjects...so your post is silly. if you want to be helpful, suggest khanacademy as another source of information without alienating everyone on this forum who is trying to be helpful and share knowledge.

sir.

and i'm sorry that you have found yourself unable/unfit to participate.

[adubas]

plenty of questions have been adequately answered in this thread, as most of us, while being weight-lifters, are students-college and high school- as well, that have studied these subjects...so your post is silly. if you want to be helpful, suggest khanacademy as another source of information without alienating everyone on this forum who is trying to be helpful and share knowledge.

sir.

and i'm sorry that you have found yourself unable/unfit to participate.

sorry brah

[DahStoryTella]

That picture hasn't been edited by a mod yet?

[IceRealm]

Chemistry

tf is this ?

A bottle of Hydrochloric Acid (HCl) has a label saying that the solution is 37% HCl by mass. If the density of the solution is 1.18 g/ml-1, determine the concentration of the solution in moles per litre.

Tried everything i know.

[snwbordr008]

mol/litre is concentration, isn't it?

[IceRealm]

mol/litre is concentration, isn't it?

Yes, it is. The way it's worded can be a bit confusing.

[snwbordr008]

Can you use Density=Mass/Volume. Then go from there? I haven't taken chem in a year so I can't be of much use but just trying to help get you started

[DahStoryTella]

So, I'm working on an assignment for Calculus; we're in the early stages, so we're doing a bit of a review.

However, I'm a bit confused with this question:
f(t) = t + 1 if -5 < t < 5; f(-6), f(-5), f(16)
I did the math, and:
f(-6) = -5
f(-5) = -4
f(16) = 17

The answer in my textbook for this question is f(-5) = -4. I completely understand it not being f(16) = 17, but why not f(-6) = -5 instead of f(-5) = -4?

[clockwork247]

So, I'm working on an assignment for Calculus; we're in the early stages, so we're doing a bit of a review.

However, I'm a bit confused with this question:
f(t) = t + 1 if -5 < t < 5; f(-6), f(-5), f(16)
I did the math, and:
f(-6) = -5
f(-5) = -4
f(16) = 17

The answer in my textbook for this question is f(-5) = -4. I completely understand it not being f(16) = 17, but why not f(-6) = -5 instead of f(-5) = -4?

can you type out the whole questions? what is it asking?

it's basically just showing the fucntion f(x) = x +1 for x between -5 and 5... then what's the questions? is it asking you to solve for x outside of that range? if so it doesn't make sense since there's no function out side of that range.

[AlexTrebek]

I need help with a paper due tomorrow. It is about the differences between Beowulf the movie and Beowulf the book. I cant come up with anything to write its supposed to be a 5 sentence per paragraph, 5 paragraph paper

[ACY]

I need help with a paper due tomorrow. It is about the differences between Beowulf the movie and Beowulf the book. I cant come up with anything to write its supposed to be a 5 sentence per paragraph, 5 paragraph paper

Screwed

[ACY]

3 Mg + N2 ---> Mg3N2
2 Al + 3 F2 ---> 2 AlF3
4 K + O2 ---> 2 K2O
Cd + I2 ---> CdI2
3 Cs + P ---> Cs3P

unreal

[DahStoryTella]

can you type out the whole questions? what is it asking?

it's basically just showing the fucntion f(x) = x +1 for x between -5 and 5... then what's the questions? is it asking you to solve for x outside of that range? if so it doesn't make sense since there's no function out side of that range.

My bad. Here's what the question is:
''Compute the indicated values of the given function.
f(t) = t + 1 if -5 < t < 5; f(-6), f(-5), f(16)''

[ACY]

I did include the chain rule with my y variables. I just factored out the y' but I made a mistake in my derivative. Should read:
[x(cosx)-sinx]/(x^2) + [y'(ycosy-siny)]/(y^2)

fuark

[cncman]

My bad. Here's what the question is:
''Compute the indicated values of the given function.
f(t) = t + 1 if -5 < t < 5; f(-6), f(-5), f(16)''

Your domain is simply restricted from -5 to 5, t can only be in between these numbers. -6 and 16 do not lie in the specified domain, only -5 does. And all you are doing is plugging -5 in for t, giving f(-5) = -4. IE: f(-5) = (-5)+1

[clockwork247]

Your domain is simply restricted from -5 to 5, t can only be in between these numbers. -6 and 16 do not lie in the specified domain, only -5 does. And all you are doing is plugging -5 in for t, giving f(-5) = -4. IE: f(-5) = (-5)+1

yep, this is what it is. any t out side of -5 to 5 is just NA, nothing there... you can confirm this by putting the function in the graphing calculator and restrict the domain, you won't get anything out side of -5 to 5.

[DahStoryTella]

Repped!

[fuarkimripped]

I'm trying to factor the difference of 2 cubes. ( a^3 - b^3 ) = ( a - b ) ( a^2 + ab + b^2 ). The problem is Y^3 - 8. I keep getting the answers ( y - 2) ( Y^2 - 2Y + 4 ). The answers is the above except that there is a positive 2y, and not a negative one in second part of my answer. Aware on what I'm doing wrong? Quick brahs I have a test on this **** Tommorrow lolz

[CanadianAthlete]

Name reasons why bottled water is dangerous compared to tap water for an essay.
Any other reasons besides chemicals?

[ThomasRe]

Anyone read Kon-tiki by Thor Heyerdahl? Please I need a quick synopsis.

[holup]

Can someone help me with this? It should be pretty easy, but I'm not sure on how to do the work.

The graph of y = (x+5)^2 + b passes through the point (3, 24). What is the value of b?

[cncman]

Can someone help me with this? It should be pretty easy, but I'm not sure on how to do the work.

The graph of y = (x+5)^2 + b passes through the point (3, 24). What is the value of b?

24 = (3+5)^2 + b
24 = 64 + b
b = -40

It gave a function with an x and y in it, and gave you an (x,y) coordinate. Simply plug them into the equation and solve for b.