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we need the preamble first, not just the graphs

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first one is D.
i think the second one is A.
im tired.

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B for velocity
D for position
If those forces are constantly applied, velocity will decrease linearly and position will be parabolic. I think this is right. Not sure why the position graph goes up at first.
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The two forces can be added together, so the net force will be to the left. This means there is a constant acceleration to the left. This implies a linear velocity (with a negative slope) and a quadratic position, also with a negative derivative. The two lines which represent this are B and D.
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i think its
B
D
velocity is the derivative of position. you know that if velocity is a x then the position has to be x^2/2 which would make it D for the position.
Last edited by charity4thepoor; 03162009 at 07:14 PM.
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Originally Posted by dealmaster
The two forces can be added together, so the net force will be to the left. This means there is a constant acceleration to the left. This implies a linear velocity (with a negative slope) and a quadratic position, also with a negative derivative. The two lines which represent this are B and D.
this r correct.

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Originally Posted by astarr22
B for velocity
D for position
If those forces are constantly applied, velocity will decrease linearly and position will be parabolic. I think this is right. Not sure why the position graph goes up at first.
you're right for the first one. i didnt think about the axes.
for the second one, you're probably right, i noticed that too.

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the forces are unbalanced and unchanging in negative direction, therefore constant negative acceleration so it has to be B for 1A. Since it's negative acceleration > D for 1B
Last edited by Jismy; 03162009 at 08:10 PM.
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