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  1. #1
    The OG of Freshness RockNvEgas's Avatar
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    This Physics Question f'ing Blows!

    1A. Which of the curves labeled A to D on the graph (Part A figure) could be a plot of v_x(t), the velocity of the object in the x direction as a function of time?


    1B. Which of the curves labeled A to D on the graph (Part B figure) could be a plot of x(t), the position of the object along the x axis as a function of time?


    EDIT: First Part:

    Two forces are exerted on an object of mass m in the x direction as illustrated in the free-body diagram. (Intro 1 figure) Assume that these are the only forces acting on the object.

    Last edited by RockNvEgas; 03-16-2009 at 06:57 PM.
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  2. #2
    The OG of Freshness RockNvEgas's Avatar
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    Halp!
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  3. #3
    Brolosopher soloS's Avatar
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    the answer is 42
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  4. #4
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    C
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  5. #5
    Registered User t3nkenx's Avatar
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    A
    B
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  6. #6
    Registered User colt.45's Avatar
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    we need the preamble first, not just the graphs
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  7. #7
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    edit: need more info
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  8. #8
    Blue Belt Beardman JewMasterKrunk's Avatar
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    first one is D.

    i think the second one is A.

    im tired.
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  9. #9
    The OG of Freshness RockNvEgas's Avatar
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    posted first part
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  10. #10
    Registered User astarr22's Avatar
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    B for velocity
    D for position

    If those forces are constantly applied, velocity will decrease linearly and position will be parabolic. I think this is right. Not sure why the position graph goes up at first.
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  11. #11
    Registered User dealmaster's Avatar
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    The two forces can be added together, so the net force will be to the left. This means there is a constant acceleration to the left. This implies a linear velocity (with a negative slope) and a quadratic position, also with a negative derivative. The two lines which represent this are B and D.
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  12. #12
    Jags Are Bake charity4thepoor's Avatar
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    i think its
    B
    D
    velocity is the derivative of position. you know that if velocity is a -x then the position has to be -x^2/2 which would make it D for the position.
    Last edited by charity4thepoor; 03-16-2009 at 07:14 PM.
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  13. #13
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    Originally Posted by dealmaster View Post
    The two forces can be added together, so the net force will be to the left. This means there is a constant acceleration to the left. This implies a linear velocity (with a negative slope) and a quadratic position, also with a negative derivative. The two lines which represent this are B and D.
    this r correct.
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  14. #14
    Registered User lurkr's Avatar
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  15. #15
    Blue Belt Beardman JewMasterKrunk's Avatar
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    Originally Posted by astarr22 View Post
    B for velocity
    D for position

    If those forces are constantly applied, velocity will decrease linearly and position will be parabolic. I think this is right. Not sure why the position graph goes up at first.
    you're right for the first one. i didnt think about the axes.
    for the second one, you're probably right, i noticed that too.
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  16. #16
    Registered User lurkr's Avatar
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  17. #17
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    the forces are unbalanced and unchanging in negative direction, therefore constant negative acceleration so it has to be B for 1A. Since it's negative acceleration -> D for 1B
    Last edited by Jismy; 03-16-2009 at 08:10 PM.
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