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09-23-2009, 04:59 AM
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#1
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Quick chemistry question *REPS*
easy question i know but i just want to check my answers
calculate the concentration of a solution prepared by dissolving 16.0g of CaCl2 in 250.0mL of solution
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09-23-2009, 05:06 AM
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#2
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bump
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09-23-2009, 05:15 AM
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#3
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16g CaCO3
CaCO3 has a molar mass of 100g/gmol
n = m/M = 16/100 = 0.16gmol
C = n/V = 0.16gmol/0.25L
C = 0.64 gmol/L = 0.64M
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09-23-2009, 05:15 AM
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#4
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Quote:
Originally Posted by Colemans#1
easy question i know but i just want to check my answers
calculate the concentration of a solution prepared by dissolving 16.0g of CaCl2 in 250.0mL of solution
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cookin meth brah?
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09-23-2009, 05:16 AM
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#5
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Quote:
Originally Posted by dat
16g CaCO3
CaCO3 has a molar mass of 100g/gmol
n = m/M = 16/100 = 0.16gmol
C = n/V = 0.16gmol/0.25L
C = 0.64 gmol/L = 0.64M
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CaCl2 not some **** u found on the net
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Thanks Ronnie, you're a true legend
Well done Dexter Jackson!!!
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"The more a man learns, he realises how little he knows"
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09-23-2009, 05:21 AM
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#6
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WILDCARD, bitches!
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Gah, eyes deceive me.
I did the bulk of the work anyway. M(CaCl2) = 111g/gmol.
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09-23-2009, 05:22 AM
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#7
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WILDCARD, bitches!
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Quote:
Originally Posted by Colemans#1
CaCl2 not some **** u found on the net
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And what the fack do you think you're doing? lol
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